0,6x^2-6x-1200=0

Solution for 0,6x^2-6x-1200=0 equation:

0.6x^2-6x-1200=0

a = 0.6; b = -6; c = -1200;
Δ = b2-4ac
Δ = -62-4·0.6·(-1200)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-54}{2*0.6}=\frac{-48}{1.2}
=-40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+54}{2*0.6}=\frac{60}{1.2}
=50
$